Список проголосовавших за комментарий "Проверка Wolframalpha: надёжность выиграть и проиграть<br/> и вероятность выигрыша и проигрыша создают 4 комбинации:<br/> C+p^N=1 … (1-C)+p^N=1 … C+(1-p)^N=1 … (1-C)+(1-p)^N=1<br/> <br/> Причём всё взаимозаменяемо:<br/> C=1-c… c=1-C… P=1-p… p=1-P<br/> <br/> Искусственный интеллект Wolframalpha знает логарифм:<br/> solve C+(1-p)^N=1 for N<br/> <br/> <a href="/r.php?u=https%3A%2F%2Fwolframalpha.com%2Finput%2F%3Fi%3Dsolve%2BC%252B%25281-p%2529%255EN%253D1%2Bfor%2BN&s=1883815940">https://wolframalpha.com/input/?i=solve+C%2B%281-p%29%5EN%3D1+for+N</a><br/> <br/> <a class="imgpreview" href="/uploads/images/05/70/34/2020/04/08/e41ea7.png"><img src="/uploads/images/05/70/34/2020/04/08/3dc8b6.png"/></a><br/> <br/> <br/> Checking in Wolframalpha: reliability win and lose<br/> both probability of winning and losing create 4 combinations:<br/> C+p^N=1 ... … (1-C)+p^N=1… C+(1-p)^N=1… (1-C)+(1-p)^N=1<br/> <br/> Everything is interchangeable:<br/> C=1-c… c=1-C… P=1-p… p=1-P<br/> <br/> Artificial intelligence of Wolframalpha knows logarithm:<br/> solve C+(1-p)^N=1 for N<br/> <br/> <a href="/r.php?u=https%3A%2F%2Fwolframalpha.com%2Finput%2F%3Fi%3Dsolve%2BC%252B%25281-p%2529%255EN%253D1%2Bfor%2BN&s=1883815940">https://wolframalpha.com/input/?i=solve+C%2B%281-p%29%5EN%3D1+for+N</a><br/> <br/> <a class="imgpreview" href="/uploads/images/05/70/34/2020/04/08/e41ea7.png"><img src="/uploads/images/05/70/34/2020/04/08/3dc8b6.png"/></a>"